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Assume that a procedure yields a binomial distribution with a trial repeated n=6 times. Use either the binomial probability formula (or a technology like Excel or StatDisk) to find the probability of k=4 successes given the probability q=0.52 of success on a single trial.

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Final answer:

To find the probability of 4 successes in a binomial distribution with 6 trials and a success probability of 0.52, we can use the binomial probability formula.

Step-by-step explanation:

To find the probability of k=4 successes in a binomial distribution with n=6 trials and a success probability of q=0.52, we can use the binomial probability formula:

P(X=k) = (nCk) * p^k * q^(n-k)

Plugging in the values, we get:

P(X=4) = (6C4) * (0.52)^4 * (0.48)^2

P(X=4) = 15 * 0.0780736 * 0.2304

P(X=4) = 0.269736

Therefore, the probability of getting 4 successes is approximate 0.27, or 27%.

User Sheheryar Sajid
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