Question

The mean height of an adult giraffe is 19 feet. Suppose that the distribution is normally distributed with standard deviation 0.9 feet. Let X be the height of a randomly selected adult giraffe. Round all answers to 4 decimal places where possible. a. What is the distribution of X?

Answer 1

The height of a randomly selected adult giraffe is normally distributed with a mean of 19 feet and a standard deviation of 0.9 feet, hence X~N(19, 0.9).

Step-by-step explanation:

The distribution of the variable X, which is the height of a randomly selected adult giraffe, can be defined by the normal distribution with a mean (μ) of 19 feet and a standard deviation (σ) of 0.9 feet. Therefore, the distribution of X is expressed as X~N(19, 0.9). In the realm of normal distribution, this implies that the heights of adult giraffes are symmetrically distributed around the mean height of 19 feet, with 0.9 feet as the measure of variability or dispersion around this mean.