Question

A commercial airliner recently diverted after a passenger died on the plane. Studies say that two passengers have died in a 10-year period. What is the probability of 1 passenger dying during the same time period?

Answer 1

To find the probability of 1 passenger dying during a 10-year period, we need to calculate the probability of at least 2 passengers dying and subtract it from 1. The given information states that two passengers have died in a 10-year period. If we assume that these deaths are independent events and the probability of a passenger dying is constant, then the probability of 2 or more passengers dying is: P(2 or more passengers dying) = 1 - P(no passengers dying) - P(1 passenger dying). Since the probability of 1 passenger dying is the complement of the probability of 2 or more passengers dying, we can rearrange the equation as: P(1 passenger dying) = 1 - P(2 or more passengers dying)

Step-by-step explanation:

To find the probability of 1 passenger dying during a 10-year period, we need to calculate the probability of at least 2 passengers dying and subtract it from 1.

The given information states that two passengers have died in a 10-year period. If we assume that these deaths are independent events and the probability of a passenger dying is constant, then the probability of 2 or more passengers dying is:

P(2 or more passengers dying) = 1 - P(no passengers dying) - P(1 passenger dying)

Since the probability of 1 passenger dying is the complement of the probability of 2 or more passengers dying, we can rearrange the equation as:

P(1 passenger dying) = 1 - P(2 or more passengers dying)