Final answer:
The union of sets A and B is {2, 4, 6, 8, 10, 12, 14, 15, 16, 17, 18, 19}. The intersection of sets B and C is {8, 10, 12, 14}. The elements that belong to set A but not set D are {15, 16, 17, 18, 19}. The complement of set C cannot be calculated without the Universal Set. The size of set B is 4.
Step-by-step explanation:
a) What is the union of sets A and B?
The union of sets A and B, denoted by A ∪ B, is the set that contains all the elements that are in either set A or set B, or in both. In this case, the union of sets A and B is {2, 4, 6, 8, 10, 12, 14, 15, 16, 17, 18, 19}.
b) What is the intersection of sets B and C?
The intersection of sets B and C, denoted by B ∩ C, is the set that contains all the elements that are common to both set B and set C. In this case, the intersection of sets B and C is {8, 10, 12, 14}.
c) List the elements that belong to set A but not to set D.
To find the elements that belong to set A but not to set D, we need to subtract the elements of set D from set A. In this case, set A = {2, 4, 6, 8, 10, 12, 14, 15, 16, 17, 18, 19} and set D = {2, 4, 6, 8, 10, 12, 14}. Subtracting set D from set A, we get {15, 16, 17, 18, 19}.
d) Calculate the complement of set C within the Universal Set.
The complement of set C, denoted by C', is the set that contains all the elements of the Universal Set that are not in set C. In this case, the Universal Set is not provided, so it is not possible to calculate the complement of set C.
e) Find the size of set B.
The size of a set is the number of elements in the set. In this case, set B = {8, 10, 12, 14}, so the size of set B is 4.