Question

Determine the margin of error for a 90% confidence interval to estimate the population mean when s-42 for the sample sizes below.

a) n=12
b) n=35
c) n=48

Answer 1

To determine the margin of error for a 90% confidence interval to estimate the population mean, use the formula: Margin of Error = Z * (s / √n), where Z is the z-score for the desired confidence level, s is the sample standard deviation, and n is the sample size.

Step-by-step explanation:

To determine the margin of error for a 90% confidence interval to estimate the population mean, we need to use the formula:

Margin of Error = Z * (s / √n)

where Z is the z-score for the desired confidence level, s is the sample standard deviation, and n is the sample size.

For the given sample sizes:

a) n = 12:

Margin of Error = 1.645 * (42 / √12) = 21.462

b) n = 35:

Margin of Error = 1.645 * (42 / √35) = 9.402

c) n = 48:

Margin of Error = 1.645 * (42 / √48) = 8.355