Final answer:
To estimate the population proportion with a margin of error at 95% confidence, the minimum sample size needed is 385.
Step-by-step explanation:
To determine the minimum sample size needed to estimate a population proportion with a margin of error at 95% confidence, we can use the formula:
n = (Z^2 * p * (1-p))/(E^2)
where n is the sample size, Z is the Z-score corresponding to the desired confidence level (Z = 1.96 for 95% confidence), p is the planning value (0.5), and E is the margin of error (0.05).
Plugging in the values into the formula:
n = (1.96^2 * 0.5 * (1-0.5))/(0.05^2) = 385
Therefore, the minimum sample size needed is 385. So, the correct answer is D. 385.