Final answer:
The MVUE for θ is 2Yn with a variance of θ2/3n. The expression n * E[(dθ / d log fY(Y1 | θ))2] simplifies to n * θ2. The lower bound on the variance of unbiased estimators of θ is θ2, but it is not valid for the uniform distribution.
Step-by-step explanation:
(a) The minimum variance unbiased estimator (MVUE) for θ in this case is 2Yn. To calculate its variance, we can use the fact that the variance of a uniform distribution on (0, θ) is θ2/12. Therefore, the variance of the MVUE is θ2/3n.
(b) The expression n * E[(dθ / d log fY(Y1 | θ))2], where fY(Y1 | θ) is the probability density function of Y1, simplifies to n * (θ2/θ)2 = n * θ2.
(c) From part (b), we can see that the lower bound on the variance of unbiased estimators of θ is θ2. However, for the uniform distribution, this lower bound is not valid because it depends on the parameter θ, which is unknown.