Question

Followingan article in The Joumal of American College Health that studied alcohol consumption on college campuses a local campus sampled 80 students who lived in campus housing and found that 52 reported they consumed alcohol weekly. Construct a 95% confidence interval to estimate the proportion of campus resident students who consume alcohol weekly. Save this answer for the essay question following this matching question. Identify the following values necessary to construct a 95% confidence interval to estimate the proportion of campus resident students who consume aicohol weekly

Answer 1

To construct a 95% confidence interval for the proportion of campus resident students who consume alcohol weekly, the necessary values include the sample proportion (52/80), the level of confidence (95%), and the standard error of the proportion.

Step-by-step explanation:

In estimating the proportion of students consuming alcohol weekly, the sample proportion is calculated as 52 students out of the total sample size of 80 who reported weekly alcohol consumption. To construct a confidence interval, the standard error of the proportion is essential, derived from the formula
`SE = sqrt((p*(1-p))/n)`, where p is the sample proportion and n is the sample size.

This standard error quantifies the variability between samples and indicates the accuracy of the estimate. With a level of confidence set at 95%, the confidence interval can be calculated around the sample proportion, providing a range within which the true proportion of campus residents who consume alcohol weekly is likely to fall.