Question

Assume that when human resource managers are randomly selected, 35% say job applicants should follow up within two weeks. If 9 human resource managers are randomly selected, find the probability that exactly 4 of them say job applicants should follow up within two weeks. The probability is (Round to four decimal places as needed.)

Answer 1

The probability of exactly 4 out of 9 human resource managers saying job applicants should follow up within two weeks when each has a 35% chance of saying so is approximately 0.1681.

Step-by-step explanation:

The student asked for the probability that exactly 4 out of 9 randomly selected human resource managers would say job applicants should follow up within two weeks, given that there is a 35% chance of any individual manager saying so. To solve this problem, we can use the binomial probability formula, which is P(X=k) = (n choose k) * p^k * (1-p)^(n-k), where 'n' is the number of trials, 'k' is the number of successes, and 'p' is the probability of success on any given trial. In this case, n=9, k=4, and p=0.35.

Using the formula, we get:
P(4) = (9 choose 4) * (0.35)^4 * (0.65)^5.

Calculating this, we find the probability to be approximately:

P(4) = 0.1681 (rounded to four decimal places).