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When it comes time to take the test not only do the s f(x)=x⁵-3x⁴-5x³+5x²-6x+8=0

User Andrei G
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1 Answer

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Final Answer:

The solution to the equation f(x) = x⁵ - 3x⁴ - 5x³ + 5x² - 6x + 8 = 0 is x = 1.

Explanation:

To solve the given equation f(x) = x⁵ - 3x⁴ - 5x³ + 5x² - 6x + 8 = 0, we can use the rational root theorem and synthetic division. By applying the rational root theorem, we find that the potential rational roots are ±1, ±2, ±4, and ±8. Upon testing these potential roots using synthetic division, we find that x = 1 is a root of the given equation. Therefore, the solution to the equation f(x) = x⁵ - 3x⁴ - 5x³ + 5x² - 6x + 8 = 0 is x = 1.

Using synthetic division: 1 | 1 -3 -5 5 -6 8

| 1 -2 -7 -2 -8

-------------------------

| 1 -2 -7 -2 0

Therefore, by synthetic division, we have (x-1)(x⁴-2x³-7x²-2x) = 0. Since x=1 is a root of the equation x⁴-2x³-7x²-2x=0, we can factorize it as (x-1)(x³-x²-6x)=0. Solving for x in this factorized form gives us x=1 as the solution to the original equation f(x)=0.

User Paul Rubel
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