Question

Suppose that A and B are events such that P(A) = 0.58, and P(B) = 0.26, and A and B are mutually exclusive. Find P(A or B).

Answer 1

To find the probability of either event A or event B occurring when they are mutually exclusive, you simply add their individual probabilities together, resulting in P(A OR B) = 0.84.

Step-by-step explanation:

The subject of the question is finding the probability of either event A or event B occurring, given that they are mutually exclusive events. The formula to use in this case is P(A OR B) = P(A) + P(B). Since the events cannot occur simultaneously (mutually exclusive), there is no need to subtract the intersection of the events. Therefore, based on the information provided that P(A) = 0.58 and P(B) = 0.26, we can calculate P(A OR B) as follows:

P(A OR B) = P(A) + P(B)

P(A OR B) = 0.58 + 0.26

P(A OR B) = 0.84