Final answer:
To find the percent of New York's state high school teachers who earn between $85,000 and $90,000, we need to calculate the z-scores for both salary values and use the standard normal distribution table.
Step-by-step explanation:
To find the percent of New York's state high school teachers who earn between $85,000 and $90,000, we need to calculate the z-scores for both salary values and use the standard normal distribution table.
We use the formula z = (x - mean) / standard deviation to calculate the z-scores.
For $85,000: z = (85000 - 99410) / 9580 = -1.4559
For $90,000: z = (90000 - 99410) / 9580 = -0.9468
Looking up the corresponding probabilities in the standard normal distribution table:
The probability of earning less than $85,000 would be the area to the left of z = -1.4559, which is 0.0726 (or 7.26% rounded to the nearest hundredth).
The probability of earning less than $90,000 would be the area to the left of z = -0.9468, which is 0.1711 (or 17.11% rounded to the nearest hundredth).
Therefore, the percent of New York's state high school teachers who earn between $85,000 and $90,000 is approximately 17.11% - 7.26% = 9.85% (rounded to the nearest hundredth).