199k views
3 votes
Suppose a special 18-sided die is rolled once where each face is marked with a number 1 through 18. What is the probability that the die lands on a 11 or a 7 ?

User J Hunt
by
7.8k points

1 Answer

1 vote

Final answer:

The probability of rolling an 11 or a 7 on an 18-sided die is 2/18, which simplifies to 1/9, or approximately 11.11%.

Step-by-step explanation:

To calculate the probability that the 18-sided die lands on an 11 or a 7, we look at the favorable outcomes and the total number of outcomes. There are two favorable outcomes (rolling an 11 or a 7), and there are 18 possible outcomes since the die has 18 sides. Therefore, we use the probability formula:

Probability (P) = Number of favorable outcomes / Total number of outcomes.

Applying this formula, the probability of landing on an 11 or 7 is:

P(11 or 7) = 2 / 18 = 1 / 9 ≈ 0.1111 or 11.11%

This means that there is an 11.11% chance that the die will land on either 11 or 7 when it is rolled once.

User Pavel Hasala
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories