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Indicate the type of hypothesis each of the following are by

indicating directional or non-directional AND null or
alternative:

1 Answer

6 votes

Final Answer:

1.
\(H_0: \mu_1 = \mu_2\), \(H_a: \mu_1 \\eq \mu_2\) - This is a non-directional and two-tailed hypothesis test.

2.
\(H_0: \mu \geq 50\), \(H_a: \mu < 50\) - This is a directional and left-tailed hypothesis test.

3.
\(H_0: \sigma_1 = \sigma_2\),
\(H_a: \sigma_1 \\eq \sigma_2\) - This is a non-directional and two-tailed hypothesis test.

4.
\(H_0: p = 0.25\), \(H_a: p > 0.25\) - This is a directional and right-tailed hypothesis test.

Step-by-step explanation:

In the first scenario,
\(H_0: \mu_1 = \mu_2\) and
\(H_a: \mu_1 \\eq \mu_2\) , it is a non-directional, two-tailed hypothesis test because it does not specify a particular direction of the difference between the population means
(\(\mu\)). The null hypothesis
(\(H_0\)) assumes equality, while the alternative hypothesis
(\(H_a\)) indicates inequality.

In the second case,
\(H_0: \mu \geq 50\) and
\(H_a: \mu < 50\), it is a directional, left-tailed hypothesis test. The null hypothesis
(\(H_0\)) states that the population mean
(\(\mu\)) is greater than or equal to 50, and the alternative hypothesis
(\(H_a\)) suggests that the population mean is less than 50.

Moving on to the third scenario,
\(H_0: \sigma_1 = \sigma_2\ and
\(H_a: \sigma_1 \\eq \sigma_2\), it is a non-directional, two-tailed hypothesis test for comparing the population standard deviations
(\(\sigma\)).

Lastly, in the fourth case,
\(H_0: p = 0.25\) and
\(H_a: p > 0.25\), it is a directional, right-tailed hypothesis test. The null hypothesis
(\(H_0\)) posits that the population proportion (p) is equal to 0.25, while the alternative hypothesis
(\(H_a\)) suggests that the population proportion is greater than 0.25.

User Lonna
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