Question

The mean perpent of childhood asthma prevalence in 43 oties is 205%. A random sample of 33 of these otes is selected. What is the probabity that the mean childhood asthma perealence for the sampie is grester than 25% ? Interpeet this probubily. Assume that 0=137%.

The probabisty is (Round to four decimal places as needed) Interpret this probabily.
Select the correct chocice below and tain the answer box to tomplete your choice (Round to two decimal places as needed)
A. About 6 of tamples of 43 olies wal have a mean chithood anthma prevalence greater han 2.5% 13. About 4 of saveles of 33 otos wila have a mesn chlosood asthma prevalence groter than 25%.

Answer 1

The question aims to determine the probability of a sample mean exceeding a certain value, but lacks sufficient information for calculation. Typically, the Central Limit Theorem and z-scores would be used, but the provided data is incomplete and contains typos.

Step-by-step explanation:

The question is asking for the probability that the mean childhood asthma prevalence for a sample of 33 cities is greater than 25% given that the mean percent of asthma prevalence in 43 cities is 20.5% and the standard deviation (σ) is 13.7%. To find this probability, one would typically use the Central Limit Theorem (CLT) and z-scores as part of a hypothesis testing framework. However, there is not enough information provided to calculate the z-score as we do not have the actual sample mean of the 33 cities. Additionally, the value of 20.5% is incorrectly written as 205% in the initial part of the question, which should be rectified to 20.5%. Given these circumstances, it's not possible to provide the exact probability without the corrected and additional necessary information.