The man can walk 10 miles into the country and ride back on the trolley in 3 hours.
Let's denote the distance the man walks into the country as 'D' (in miles) and the time he spends walking as 'T' (in hours).
Since he must be back home 3 hours from the time he started, the total time spent walking and riding the trolley is:
Total time = 3 hours - Time to walk into the country - Time to ride back
We know that the time to walk into the country is D/4 hours (distance divided by speed) and the time to ride back is D/20 hours. Substituting these values into the total time equation, we get:
3 hours = D/4 + D/20
To solve for D, we can multiply both sides of the equation by the least common multiple of the denominators, which is 20:
60 hours = 5D + D
Combining like terms, we get:
60 hours = 6D
Dividing both sides by 6, we find the distance:
D = 10 miles
Therefore, the man can walk 10 miles into the country and ride back on the trolley in 3 hours.
Question
3. A man walks at the rate of 4 miles per hour. How far can he walk into the country and ride back on a trolley that travels at the rate of 20 miles per hour, if he must be back home 3 hours from the time he started?​