Question

The mean percent of childhood asthma prevalence in 43 cities is 2.38%. A random sample of 32 of these cities is s childhood asthma prevalence for the sample is greater than 2.6%? Interpret this probability. Assume that σ= 1.22% elected. What is the probability that the mean The probability is 8461 (Round to four decimal places as needed.)

Answer 1

To calculate the probability of the mean childhood asthma prevalence for a sample of 32 cities being greater than 2.6%, we can use the Central Limit Theorem and z-scores.

Step-by-step explanation:

In order to determine the probability that the mean childhood asthma prevalence for a random sample of 32 cities is greater than 2.6%, we can use the Central Limit Theorem.

1. First, we need to calculate the standard deviation of the sampling distribution, also known as the standard error. This can be found by dividing the population standard deviation (1.22%) by the square root of the sample size (32).
2. Next, we can calculate the z-score, which measures how many standard errors the sample mean is away from the population mean. The formula for the z-score is: z = (sample mean - population mean) / standard error.
3. Finally, we can use a standard normal distribution table or a calculator to find the probability of obtaining a z-score greater than the calculated value. In this case, the probability is approximately 0.8461.