62.1k views
3 votes
"Let X be a binomial random variable with parameters n and p. Show that E[X + 1] = (n + 1)p / (1 - (1 - p)^(n + 1))."

User Tassadaque
by
8.4k points

1 Answer

5 votes

Final answer:

To calculate E[X + 1] for a binomial random variable with parameters n and p, we first find the expected value of X and then add 1.

Step-by-step explanation:

To show that E[X + 1] = (n + 1)p / (1 - (1 - p)^(n + 1)), we need to calculate the expected value of X + 1. The expected value of a random variable is the sum of the products of each possible value of the variable and its corresponding probability.

First, let's calculate the expected value of X:

  • The expected value of X, denoted as E[X], is given by E[X] = np.

Next, we need to calculate the expected value of X + 1:

  • We can rewrite X + 1 as X + 1 = X + 1 * 1.
  • Using the linearity of expectation, we have E[X + 1] = E[X] + E[1].
  • The expected value of 1 is 1, so we have E[X + 1] = E[X] + 1.
  • Substituting E[X] = np, we get E[X + 1] = np + 1.

Finally, rearranging the equation, we have E[X + 1] = (n + 1)p.

So, the expression E[X + 1] = (n + 1)p / (1 - (1 - p)^(n + 1)) is correct.

User Ran Eldan
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories