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Assuming a normal distribution, what is the probability of randomly selecting a z-score greater than z = 1.16?

probability

User Baijum
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Final answer:

To find the probability of a z-score greater than 1.16 in a standard normal distribution, you subtract the table value for z = 1.16 from 1, providing an approximate chance of 12.38% for a z-score above 1.16.

Step-by-step explanation:

The probability of randomly selecting a z-score greater than z = 1.16 from a standard normal distribution can be found by looking at a Z-Table or using a statistical software. The standard normal distribution is denoted as Z ~ N(0, 1), which means it has a mean of 0 and a standard deviation of 1. To find the probability for a z-score greater than 1.16, you would need to find the area under the standard normal curve to the right of this z-score.

Since most Z-Tables provide the area to the left of a z-score, you would subtract this value from 1 to get the area to the right. For example, if the Z-Table indicates that the area to the left of z = 1.16 is 0.8762, then the probability of a z-score greater than 1.16 is:

1 - 0.8762 = 0.1238

This means there is approximately a 12.38% chance of randomly selecting a z-score greater than 1.16.

User Viscocent
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