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What is the sample size if the standard error is 0.02 and the
proportion is p=0.8?

User Rahsaan
by
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1 Answer

4 votes

Final answer:

The sample size is 3841

Step-by-step explanation:

The sample size can be calculated by using the formula:

n = (z^2 * p' * q') / E^2

where n is the sample size, z is the z-score corresponding to the desired confidence level, p' is the sample proportion, q' is 1 - p', and E is the standard error.

In this case, the standard error is given as 0.02 and the proportion is p=0.8. Let's assume a desired confidence level of 95%, which corresponds to a z-score of 1.96. Plugging these values into the formula:

n = (1.96^2 * 0.8 * 0.2) / (0.02^2) = 3841

Therefore, the sample size is 3841.

User Zznate
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