Question

In a clinical trial of a drug intended to help people stop smoking, 134 subjects were treated with the drug for 13 weeks, and 11 subjects experienced abdominal pain. if someone claims that more than 8% of the drugs users experience abdominal pan, that claim is supported with a hypothesis test conducted with a 005 sign cance level. Using 0.16 as an altenative value of p, the power of the test is 0.96. Interpret this value of the power of the test hypot esis of p=□when the true p portion is actualy□That is, if the % chance of supporting the clam that the proportion of users who expen ▼ The power of 0.96 shows that there is a proportion o users who exper ence a do abdominal pains | ▼| than 0.08. %chance of rejectig the nal an is actualy□ then there is a e (Type integers or decimals. Do not round.)

Answer 1

The power of the test is 0.96, indicating a high likelihood of correctly rejecting the null hypothesis when it is false.

Step-by-step explanation:

The power of the test is 0.96, which means that there is a 96% chance of correctly rejecting the null hypothesis when it is false. In this case, the null hypothesis is that the proportion of drug users who experience abdominal pain is equal to or less than 8%. The alternative hypothesis is that the proportion is greater than 8%.

With a power of 0.96, it is highly likely that if the true proportion of users who experience abdominal pain is indeed 16% (0.16), the test will correctly identify this and reject the null hypothesis. This implies that there is strong evidence to support the claim that more than 8% of the drug users experience abdominal pain.