Final answer:
Using standard normal distribution methods, we calculate Z-scores to find the probabilities of consuming more than, between, or less than certain amounts of bottled water and solve for the number of gallons that 95% of people consumed less than.
Step-by-step explanation:
To solve these problems involving the standard normal distribution, we will use the Z-score formula, which is Z = (X - μ) / σ, where X is the value in question, μ is the mean, and σ is the standard deviation. For the calculations, we can use the Z-table, a calculator, or statistical software to find the probabilities.
a. To find the probability that someone consumed more than 34 gallons, we calculate the Z-score for 34 gallons and look up the corresponding area to the right of this Z-score in the standard normal distribution table. Z = (34 - 34.4) / 12 = -0.0333. The probability of consuming more than 34 gallons corresponds to 1 - P(Z ≤ -0.0333), which can be found in the table.
b. To find the probability that someone consumed between 25 and 35 gallons, we calculate the Z-scores for both values and find the area between these Z-scores. Z1 = (25 - 34.4) / 12, Z2 = (35 - 34.4) / 12. The probability is P(25 ≤ X ≤ 35) = P(Z1 ≤ Z ≤ Z2).
c. To find the probability that someone consumed less than 25 gallons, we calculate the Z-score for 25 gallons and look up the corresponding area to the left of this Z-score. Z = (25 - 34.4) / 12. The probability is P(X < 25) = P(Z ≤ Z-score for 25 gallons).
d. To find the number of gallons that 95% of people consumed less than, we refer to the standard normal distribution table to find the Z-score that corresponds to a cumulative area of 0.95. Then we solve for X using the Z-score formula in reverse: X = Zσ + μ.