Final answer:
The student needs to calculate the pmf for X and Y, the expected values E(X) and E(Y), and the variances Var(X) and Var(Y) of a random class selection scenario. This involves using probabilities based on the class sizes and calculating the means and variances accordingly.
Step-by-step explanation:
Probability Mass Function (pmf) and Expected Values
Let us tackle the problem part by part:
- Probability mass function for X: Since X is the size of the group to which a randomly chosen student belongs, we can define the pmf of X as: P(X = 15) = 15/60, P(X = 20) = 20/60, P(X = 25) = 25/60.
- Probability mass function for Y: Since Y is the size of a randomly chosen group, each group has an equal chance of being selected, so: P(Y = 15) = 1/3, P(Y = 20) = 1/3, P(Y = 25) = 1/3.
- Expected value for X (E(X)): E(X) is calculated as: E(X) = (15 * 15/60) + (20 * 20/60) + (25 * 25/60).
- Expected value for Y (E(Y)): E(Y) is calculated as: E(Y) = (15 * 1/3) + (20 * 1/3) + (25 * 1/3).
- Variance of X (Var(X)): Var(X) is the expectation of the squared deviation of X from its mean: Var(X) = ((15 - E(X))^2 * 15/60) + ((20 - E(X))^2 * 20/60) + ((25 - E(X))^2 * 25/60).
- Variance of Y (Var(Y)): Var(Y) is the expectation of the squared deviation of Y from its mean: Var(Y) = ((15 - E(Y))^2 * 1/3) + ((20 - E(Y))^2 * 1/3) + ((25 - E(Y))^2 * 1/3).
To solve the problems:
- First, calculate the values of E(X) and E(Y) using the provided pmfs.
- Then, use the calculated means to compute the variances Var(X) and Var(Y).