Question

A bag contains 6 green and 8 red jellybeans. How many ways can 4 jellybeans be withdrawn from the bag so that the number of green ones withdrawn will be less than 3 ?

Answer 1

You calculate the combinations for each scenario separately where you have 0, 1, or 2 green jellybeans, and then sum up these combinations to get the total number of ways.

Step-by-step explanation:

The question asks for the number of ways to withdraw 4 jellybeans from a bag containing 6 green and 8 red jellybeans, so that fewer than 3 green ones are withdrawn. This problem falls under the category of combinatorial mathematics, which is often included in high school mathematics curriculum. To solve this, we can consider the possible combinations of green and red jellybeans that satisfy the condition (fewer than 3 green).

• 0 green and 4 red
• 1 green and 3 red
• 2 green and 2 red

The total number of ways can be found by calculating the combinations for each scenario separately, using the combination formula C(n, k) = n! / (k! * (n-k)!), where 'n' is the total number of items, 'k' is the number of items to choose, and '!' denotes factorial. The sum of all these scenarios will give us the answer to the problem.