Final answer:
The group of probabilities (1/6), (3/6), (1/6) is valid because the sum of the probabilities is equal to 1 and each probability is between 0 and 1.
Step-by-step explanation:
The group of probabilities (1/6), (3/6), (1/6) is valid because:
- The sum of the probabilities is equal to 1. (1/6) + (3/6) + (1/6) = 1.
- Each probability is between 0 and 1, inclusive.
Therefore, the group of probabilities is valid.