Final answer:
To calculate the probability of getting at least one head when a coin is tossed 10 times, we subtract the probability of getting no heads (1/1024) from 1, resulting in a probability of 1023/1024.
Step-by-step explanation:
The question is asking to calculate the probability of getting at least one head when a coin is tossed 10 times. To find this, it is easier to calculate the probability of the complementary event, which is getting no heads (or all tails) in 10 coin tosses, and then subtract that from 1 (the certainty of all possible outcomes).
The probability of getting tails in one toss is 0.5 or ½. Thus, the probability of getting 10 tails in 10 tosses is ½10 or 1/1024. Therefore, the probability of getting at least one head in 10 tosses is 1 minus the probability of getting 10 tails, which equals:
1 - ½10 = 1 - 1/1024 = 1023/1024.
So when content loaded A coin is tossed 10 times, the probability of getting at least one head and entering the answer as a fraction inside the box is 1023/1024. Do not simplify the fraction.