Question

Find the z-score corresponding to a score of 52 from a normal distribution with a mean of 48 and S.D of 1.8. By using the Z-score table, find the area of both Z-scores?

Answer 1

To find the z-score corresponding to a score of 52 from a normal distribution with a mean of 48 and standard deviation of 1.8, we use the formula z = (x - mean) / standard deviation. The z-score is approximately 2.22.

Step-by-step explanation:

The z-score corresponding to a score of 52 from a normal distribution with a mean of 48 and standard deviation of 1.8 can be calculated using the formula:

z = (x - mean) / standard deviation

Substituting the values, we get:

z = (52 - 48) / 1.8 = 2.22

The area to the left of a z-score of 2.22 can be found by looking it up in the z-table. However, since a z-value of 2.22 is not commonly listed in the table, you can use the closest z-value for reference. For example, the area to the left of a z-score of 2.2 is 0.9861.