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Find the value of c for which the function

f(x, y) = cy(2y − x), x = 0, 3 y = 0, 1, 2

can serve as the joint probability mass function of two random variables.

User Borancar
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1 Answer

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Final answer:

To find the value of c for the function to be a joint PMF, we ensure all probabilities are non-negative and their sum equals 1, leading to the conclusion that c must be 1/14.

Step-by-step explanation:

To determine the value of c such that the function f(x, y) = cy(2y - x) serves as a joint probability mass function (PMF) for two discrete random variables, we must ensure that the PMF satisfies two conditions:


  • All probabilities must be non-negative.

  • The sum of all probabilities must be equal to 1.

Given that x can take the values 0 or 3, and y can take the values 0, 1, or 2, we first check if f(x, y) is non-negative for all these value combinations. It is, as y and (2y - x) are either zero or positive for the given values of x and y. Next, we calculate the sum of probabilities for all possible pairs of (x, y):

Σf(x, y) = f(0,0) + f(0,1) + f(0,2) + f(3,0) + f(3,1) + f(3,2)

Inserting the actual function into the equation:

c(0)(2*0 - 0) + c(1)(2*1 - 0) + c(2)(2*2 - 0) + c(0)(2*0 - 3) + c(1)(2*1 - 3) + c(2)(2*2 - 3)

Which simplifies to:

c * (0 + 2 + 8 + 0 + (-1) + 5)

Therefore, we have:

c * 14 = 1

To find c, we solve the equation:

c = 1/14

Thus, c must be 1/14 for f(x, y) to serve as a legitimate PMF.

User Liao
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