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The following table is based on information from the U.S. Census Bureau regarding the type of health insurance coverage of people by age in the year 2006: Age Health Insurance Coverage <18 45-64 >64 18-44 (B) (A) (c) (D) 373 545 390 179 Private (P) Government (G) None (N) 210 115 105 315 85 260 100 35 Find P(P or D) Answer:

User Olympian
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Final answer:

The answer to the student's question involves calculating the probability of either having private insurance or being aged 18-44. This requires summing the individuals with private insurance and those in the age group 18-44 and subtracting the intersection of the two categories.

Step-by-step explanation:

The student's question relates to calculating the probability of having either private health insurance or being in the age group 18-44 (denoted D). The table provided gives data on health insurance coverage by age in the year 2006. The information to solve this is in segment (P) for private health insurance and (D) for the 18-44 age group. We use the formula P(P ∨ D) = P(P) + P(D) - P(P ∩ D).

We add the totals of private health insurance across all age groups to find P(P). Then, we take the total of the 18-44 age group, regardless of their insurance type, to find P(D). We subtract the intersection, which is individuals from the 18-44 age group who have private insurance, already counted in both.

After calculating the total number of individuals for each (P and D) and subtracting the intersection, we arrive at the probability of an individual either having private health insurance or being aged 18-44.

User Jayaprada
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