Final answer:
The probability that Raheem missed 2 consecutive free throws in a game depends on the total number of free throws attempted and the probability of missing a free throw.
Step-by-step explanation:
To find the probability that Raheem missed 2 consecutive free throws in a game, we need to know the total number of free throws he attempted and the number of times he missed 2 consecutive throws.
Let's say Raheem attempted n free throws in a game. The probability of missing a free throw is p. Assuming each free throw is independent, the probability of missing 2 consecutive free throws is p2. So the probability that Raheem missed 2 consecutive free throws in a game is p2*n.
For example, if Raheem attempted 10 free throws and the probability of missing a free throw is 0.2, then the probability that he missed 2 consecutive free throws is 0.22 * 10 = 0.04 * 10 = 0.4.