Final answer:
The standard deviation for the sample sum distribution, given a population mean of 238 and a population standard deviation of 10 with a sample size of 75, is approximately 86.60 when rounded to two decimal places.
Step-by-step explanation:
The student is focused on applying the Central Limit Theorem for Sums to calculate the standard deviation of the sample sum distribution in a statistics problem. We are given a population mean (μ) of 238 and a population standard deviation (σ) of 10. A sample of size n = 75 is considered for the sum of the values.
To find the standard deviation for the sample sum, we multiply the population standard deviation by the square root of the sample size:
σsum = σ * √n
σsum = 10 * √75
σsum = 10 * 8.66
σsum = 86.6 (rounded to two decimal places)
Therefore, the standard deviation for the sample sum distribution is approximately 86.60.