Final answer:
To find the probability that Raheem missed 2 free throws each game, we can use conditional probability. The probability is found by multiplying the probability of missing the first shot by the probability of missing the second shot given that he missed the first.
Step-by-step explanation:
To find the probability that Raheem missed 2 free throws each game, we can use conditional probability.
Let's assume that the probability of missing a free throw is p.
We know that p^2 = 0.85 (probability of missing both shots given that he missed the first). Solving for p, we get p = sqrt(0.85).
To find the probability that he missed 2 free throws, we multiply the probability of missing the first shot (p) by the probability of missing the second shot given that he missed the first (p):
P(miss both shots) = p * p = sqrt(0.85) * sqrt(0.85) = 0.85