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Assuming the binomial distribution is appropriate, if N = 6 and P(heads) = 0.50, the probability of getting at least 5 heads

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Final answer:

The probability of getting at least 5 heads with N=6 and P(heads)=0.50 is approximately 40.63%.

Step-by-step explanation:

The probability of getting at least 5 heads can be calculated using the binomial distribution formula. In this case, N = 6 (number of trials) and P(heads) = 0.50 (probability of success).

To calculate the probability, we need to find the sum of the probabilities of getting exactly 5 heads, exactly 6 heads, and so on, up to 6 heads. We can use the binomial probability formula or a binomial distribution calculator to find these probabilities.

For example, using a binomial distribution calculator, we find that the probability of getting exactly 5 heads is approximately 0.3125, and the probability of getting exactly 6 heads is approximately 0.0938. To find the probability of getting at least 5 heads, we add these two probabilities together: 0.3125 + 0.0938 = 0.4063, or approximately 40.63%.

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