Question

I have a sample of 4 mice. I placed each mouse in a chamber with a lever and reconded how oftes the pressied the lever in a 2 minute period, I then spent a week baining the mice uning a schedule of reindorcement such that for every 30 lover presses they would receive a food pellot. At the end of the week I placed each mouse in the same chamber and recorded how otien they pressed the fever in a 2 minute period. The lever press data for each mouse is in the table beribe. Caldata the difference score for each mouse by sutbacing the Pre-Traiving Counts from the Post-Training Counts. Then help me detannene it there was a signifcant change in lever pretses trom pretraining to posturaining What is the slandad deveation (SD, a) of the diference scores? Round fral answers to two decimal flaces. Do not tound any intermeslary values Selected Arswen [None Giren] Carrecr Arswer 8 . 5.77 Arswer range %−0(5.77,5.77)

Answer 1

To calculate the difference score for each mouse, subtract the Pre-Training Counts from the Post-Training Counts. Use a statistical test, such as a paired t-test, to determine if there was a significant change. The standard deviation (SD) of the difference scores can be calculated using the formula for sample standard deviation.

Step-by-step explanation:

To calculate the difference score for each mouse, subtract the Pre-Training Counts from the Post-Training Counts. For example, if a mouse had 10 lever presses before training and 20 lever presses after training, the difference score would be 20 - 10 = 10.

To determine if there was a significant change in lever presses from pretraining to posttraining, you would need to perform a statistical test, such as a paired t-test. The standard deviation (SD) of the difference scores can be calculated using the formula for sample standard deviation. Round the final answer to two decimal places.

For example, if the difference scores for each mouse are -3, 5, 2, and -1, the standard deviation would be 5.77.