Final answer:
The volume of the weather balloon at -32.0°C, assuming constant pressure, is -251 L.
Step-by-step explanation:
According to Charles's law, the volume of a gas is directly proportional to its temperature when pressure is held constant.
In this case, the initial temperature of the weather balloon is 0.00°C and its initial volume is 22.0 L. To find the volume at -32.0°C, we can use the formula:
V1 / T1 = V2 / T2
Substituting the known values:
22.0 L / (0°C + 273) = V2 / (-32°C + 273)
Simplifying the equation gives:
V2 = (22.0 L * (241 K / 241 K)) - 273
V2 = 22.0 L - 273
V2 = -251 L
Therefore, the volume of the weather balloon at -32.0°C assuming constant pressure is -251 L.