Question

The numbers of successes and the sample sizes for independent simple random samples from two populations are provided for a left-tailed test and an 80 si conifence intervat. Complete parts (a) through (d). π ₁=12,n₁=80,π₂=13,n₂=60,a=0.10

Click here to view a table of atoas under the standard nogmal curve for nogatwo values of z Click hese bo view a table of areas. under the standard normal cunw lor positive values of z. a. Detertine the sample proportions Determine the sample proportion p^ₛ .p^₁= (Type an integer or a decimal. Round to three decimal places as needed).

Answer 1

The sample proportions for the two populations are calculated by dividing the number of successes by the sample size for each population, resulting in p^1 = 0.150 and p^2 ≈ 0.217.

Step-by-step explanation:

To determine the sample proportion p^ for the provided data, we take the number of successes π and divide it by the sample size n. In the case of the first population, we have 12 successes out of 80 trials, so the sample proportion p^1 is 12/80 or 0.150.

For the second population, we have 13 successes out of 60 trials, and thus the sample proportion p^2 is 13/60 or approximately 0.217.