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The amount of time required to assemble a component on a factory assembly line is normally distributed with a mean of 3.1 minutes and a standard deviation of 0.6 minute. Find the probability that a randomly selected employee will take the given amount of time to assemble the component. (Round your answers to four decimal places.)

(a) more than 3.8 minutes

(b) between 1.8 and 2.5 minutes

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Final answer:

To find the requested probabilities in a normally distributed variable, calculate the Z-scores and then use a Z-table or calculator to find the area under the normal curve for the calculated Z-scores.

Step-by-step explanation:

The question relates to finding probabilities for a normally distributed variable, specifically the time taken to assemble a component in a factory setting. Given that the time is normally distributed with a mean (μ) of 3.1 minutes and a standard deviation (σ) of 0.6 minutes, we can find the desired probabilities using the standard normal distribution (Z-score).

(a) Probability of taking more than 3.8 minutes: First, calculate the Z-score for 3.8 minutes using the formula Z = (X - μ) / σ, where X is 3.8. Then, use the Z-table or a calculator with normal distribution functions to find the probability that Z is larger than the calculated value.

(b) Probability of taking between 1.8 and 2.5 minutes: Repeat the process for calculating Z-scores, now for X = 1.8 and X = 2.5. The sought probability is the area under the normal curve between these two Z-scores.

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