Question

Determine the margin of error for a 90% confidence intorval to estimate the population mean when 5=35 for the sample sizes below. a) n=10 b) n=26 c) n=50 a) The margin of error for a 90% confidence interval when n=10 is (Round to two decinal places as needed.)

Answer 1

The margin of error for a 90% confidence interval when n=10 is 2.26.

Step-by-step explanation:

The margin of error for a 90% confidence interval when n=10 is 2.26.

To determine the margin of error, we use the formula:

Margin of error = Z * (Sample standard deviation / √n)

Given that the sample standard deviation (s) is 5, Z is the z-score corresponding to a 90% confidence level, which is approximately 1.645, and n is 10, we substitute these values into the formula to find:

Margin of error = 1.645 * (5 / √10) = 2.26