Final answer:
To find the probability that the sample proportion falls between 0.37 and 0.45, we use the normal distribution and the z-score formula. We calculate the standard deviation of the sample proportion using the given population proportion and sample size, and then find the z-scores for the lower and upper limits. Using a standard normal distribution table or calculator, we find the probability to be approximately 0.9907.
Step-by-step explanation:
To find the probability that the sample proportion for an SRS of size n=1020 falls between 0.37 and 0.45, we need to use the normal distribution. Since the sample proportion follows a normal distribution when the sample size is large, we can use the z-score formula to standardize the sample proportion. The formula for z-score is:
z = (p - p) / σ
where p is the sample proportion, p is the population proportion, and σ is the standard deviation of the sample proportion. In this case, p is 0.41 and σ can be approximated by:
σ = √((p(1-p))/n)
Substituting the values, we have:
σ = √((0.41(1-0.41))/1020)
Calculating gives us σ ≈ 0.0153
Now we can calculate the z-scores for the lower and upper limits:
z1 = (0.37 - 0.41) / 0.0153 ≈ -2.614
z2 = (0.45 - 0.41) / 0.0153 ≈ 2.614
Using a standard normal distribution table or calculator, we can find the probability that a standard normal variable falls between -2.614 and 2.614 to be approximately 0.9907.