Final answer:
The proportion of students that will get an A+ if the bell curve is applied is approximately 0.28%.
Step-by-step explanation:
To determine the proportion of students who will get an "A+" grade after applying the bell curve, we need to find the Z-score corresponding to a grade of 90 under the original distribution and then find the corresponding percentile in the new distribution.
For the original distribution with mean
�
1
=
57
μ
1
=57 and standard deviation
�
1
=
12
σ
1
=12, we calculate the Z-score for a grade of 90 using the formula:
�
=
�
−
�
1
�
1
Z=
σ
1
X−μ
1
where
�
X is the grade. Substituting in the values:
�
=
90
−
57
12
=
2.75
Z=
12
90−57
=2.75
Now, we use the Z-table to find the percentile corresponding to a Z-score of 2.75. The Z-table provides the probability that a standard normal random variable is less than or equal to a given Z-score.
Looking up the Z-score of 2.75 in the Z-table, we find the corresponding probability, let's call it
�
1
P
1
.
Now, for the new distribution with mean
�
2
=
77
μ
2
=77 and standard deviation
�
2
=
8
σ
2
=8, we find the Z-score for a grade of 90 using the same formula:
�
=
�
−
�
2
�
2
Z=
σ
2
X−μ
2
Substituting in the values:
�
=
90
−
77
8
=
1.625
Z=
8
90−77
=1.625
Now, using the Z-table, we find the corresponding probability, let's call it
�
2
P
2
.
The proportion of students who will get "A+" after applying the bell curve is the difference between
�
1
P
1
and
�
2
P
2
:
Proportion of A+
=
�
1
−
�
2
Proportion of A+=P
1
−P
2
This proportion represents the percentage of students who will get an "A+" grade under the new distribution. Note that we do not need to interpolate since the Z-table provides probabilities for specific Z-scores.