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Suppose the number of TV's in a household has a binomial distribution with parameters n=8 and p=10%.

Find the probability of a household

a) 2 or 6 tvs

b) 4 or fewer tvs

c) 2 or more tvs

d) fewer than 6 tvs

e) more than 4 tvs

1 Answer

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Final answer:

The probabilities for different numbers of TV's in a household, which follows a binomial distribution with parameters n=8 and p=10%, can be calculated using the binomial probability formula and adding or subtracting to find cumulative probabilities as needed.

Step-by-step explanation:

The question involves finding probabilities for a binomial distribution with parameters n=8 and p=0.10. For any given number of TVs (k), the probability can be found using the binomial probability formula:

P(X=k) = C(n, k) * p^k * (1-p)^(n-k)

Where C(n, k) is the combination of n items taken k at a time.

  • a) Probability of 2 or 6 TVs: We calculate for P(X=2) and P(X=6) separately and then add them together since these are two distinct outcomes.
  • b) Probability of 4 or fewer TVs: We sum up P(X=k) for k=0 through k=4.
  • c) Probability of 2 or more TVs: Here, we can find P(X < 2) and subtract it from 1 (the total probability) to get P(X ≥ 2).
  • d) Probability of fewer than 6 TVs: This will be the cumulative probability of P(X=0) through P(X=5).
  • e) Probability of more than 4 TVs: Similarly, we can find P(X ≤ 4) and subtract from 1 to get P(X > 4).

To calculate these probabilities, one can use a binomial probability table, a calculator with a binomial probability function, or manual calculations using the formula provided.

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