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Guadalupe pulls out her famous bag o' marbles. As everyone knows, there are 5 red, 8 white, and 14 blue marbles in her bag.

a) What is the probability that if she pulls one marble it is white?
b) What is the probability that if she pulls two marbles, with replacement, they are red and then blue?
c) What is the probability that if she pulls three marbles, without replacement, they are red, then white, and then blue?

User Pilchard
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1 Answer

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Final answer:

The probabilities for drawing marbles of specific colors are calculated based on the total number of marbles and the specific conditions of replacement and non-replacement. The probability of drawing a white marble is 8/27, the probability of drawing a red and then a blue marble with replacement is (5/27) * (14/27), and the probability of drawing a red, a white, and then a blue marble without replacement is (5/27) * (8/26) * (14/25).

Step-by-step explanation:

Probability of Drawing Marbles

Let's solve each part of the question one by one:

a) Probability of drawing a white marble:

There are 5 red, 8 white, and 14 blue marbles. The total number of marbles is 5 + 8 + 14 = 27. The probability of drawing one white marble is the number of white marbles divided by the total number of marbles, which is 8/27.

b) Probability of drawing a red marble and then a blue marble, with replacement:

The probability of drawing a red marble is 5/27. Since we're replacing the marble, the probability of then drawing a blue marble remains the same: 14/27. Thus, the combined probability is the product of the two probabilities: (5/27) * (14/27).

c) Probability of drawing a red, a white, and then a blue marble, without replacement:

The probability of drawing a red marble first is 5/27. After drawing a red marble, there are 26 marbles left. The probability of drawing a white marble now is 8/26. After that, there are 25 marbles left, and the probability of drawing a blue marble is 14/25. The combined probability is the product: (5/27) * (8/26) * (14/25).

User Vlad Savitsky
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