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A survey of 24 randomly sampled judges employed by the state of Florida found that they earned an average wage (including benefits) of $65.00 per hour. The sample standard deviation was $5.72 per hour. (Use tDistribution Table.) a. What is the best estimate of the population mean? Estimated population mean b. Develop a 90% confidence interval for the population mean wage (including benefits) for these employees. (Round your answers to 2 decimal places.) Confidence etween interval for the population mean wage is an c. How large a sample is needed to assess the population mean with an allowable error of $100 at 98% confidence? Round up your answer to the next whole number.) Sample size

User Diah
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Final answer:

a. The estimated population mean is $65.00 per hour. b. The 90% confidence interval for the population mean wage is approximately $63.24 to $66.76. c. A sample size of at least 110 is needed to assess the population mean with an allowable error of $100 at 98% confidence.

Step-by-step explanation:

a. Estimated population mean:

The best estimate of the population mean is the sample mean, which is $65.00 per hour.

b. 90% confidence interval:

To calculate the confidence interval for the population mean wage, we can use the formula:

CI = X ± (t * (S/sqrt(n)))

Where:

X = Sample mean ($65.00)

t = t-score from the t-distribution table for the desired confidence level (90% confidence corresponds to a t-score of approximately 1.70)

S = Sample standard deviation ($5.72)

n = Sample size (24)

Plugging in the values, we have:

CI = $65.00 ± (1.70 * ($5.72/sqrt(24)))

Calculating this, we find that the 90% confidence interval for the population mean wage is approximately $63.24 to $66.76.

c. Sample size:

To determine the sample size needed to assess the population mean with an allowable error of $100 at 98% confidence, we can use the formula:

n = ((Z * S)/E)^2

Where:

n = Sample size

Z = Z-score from the standard normal distribution table for the desired confidence level (98% confidence corresponds to a Z-score of approximately 2.33)

S = Population standard deviation (given as $5.72 in the sample)

E = Allowable error ($100)

Plugging in the values, we have:

n = ((2.33 * $5.72)/$100)^2

Calculating this, we find that a sample size of at least 110 is needed to assess the population mean with an allowable error of $100 at 98% confidence.

User Sameer Arora
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