Final answer:
To compute the margin of error at a 95% confidence level, we use the formula Margin of Error = Z * (Standard Deviation / √(n)), where Z is the z-value for the desired confidence level. The margin of error represents the maximum amount by which the sample mean can differ from the population mean while still being within the desired confidence level. The 95% confidence interval for the population mean weight of checked bags at the airport is approximately 40.1552 to 41.8448 pounds.
Step-by-step explanation:
To compute the margin of error, we can use the formula:
Margin of Error = Z * (Standard Deviation / √(n))
where Z is the z-value corresponding to the desired confidence level, Standard Deviation is the standard deviation of the sample, and n is the sample size.
For a 95% confidence level, the z-value is approximately 1.96. Plugging in the values, we get:
Margin of Error = 1.96 * (5 / √(121))
Calculating this, we find that the margin of error is approximately 0.8448 pounds.
The margin of error represents the maximum amount by which the sample mean can differ from the population mean while still being within the desired confidence level.
To determine the confidence interval for the population mean weight of checked bags at the airport, we can use the formula:
Confidence Interval = Sample Mean ± Margin of Error
Plugging in the values, we get:
Confidence Interval = 41 ± 0.8448
Calculating this, we find that the 95% confidence interval for the population mean weight of checked bags at the airport is approximately 40.1552 to 41.8448 pounds.