25.7k views
2 votes
If a seed is planted, it has a 85 % chance of growing into a healthy plant. If 7 seeds are planted, what is the probability that exactly 1 doesn't grow?

1 Answer

4 votes

Final answer:

To find the probability that exactly 1 seed doesn't grow out of 7 planted seeds, we can use the binomial probability formula. Plugging in the values, we get a probability of approximately 0.000012625945.

Step-by-step explanation:

To find the probability that exactly 1 seed doesn't grow out of 7 planted seeds, we need to use the binomial probability formula.

The formula is:

P(X=k) = C(n,k) imes p^k imes (1-p)^(n-k)

Where:

P(X=k) is the probability of getting exactly k successes,

C(n,k) is the number of combinations of n items taken k at a time,

p is the probability of success,

n is the number of trials

k is the number of successful trials.

In this case, n = 7 (number of seeds planted), p = 0.85 (probability of seed growing), and k = 1 (exactly 1 seed doesn't grow).

Plugging in the values into the formula:

P(X=1) = C(7,1) imes 0.85^1 imes (1-0.85)^(7-1)

P(X=1) = 7 imes 0.85 imes 0.15^6

P(X=1) = 7 imes 0.85 imes 0.000002076299

P(X=1) ≈ 0.000012625945

Therefore, the probability that exactly 1 seed doesn't grow out of 7 planted seeds is approximately 0.000012625945.

User Logan Guo
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories