Final answer:
To calculate the margin of error at a 95% confidence level when n=340 and p-hat=0.62, use the formula: ME = (z)(√(p-hat(1-p-hat))/√n). Substituting the given values into the formula, we get a margin of error of approximately 0.038.
Step-by-step explanation:
To calculate the margin of error at a 95% confidence level, we can use the formula:
ME = (z)(√(p-hat(1-p-hat))/√n)
Where:
Substituting the given values into the formula:
ME = (1.96)(√((0.62)(1-0.62))/√340) ≈ 0.038
So, the margin of error at a 95% confidence level is approximately 0.038.