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A constant torque of 32.0 Nm can bring a flywheel starting from rest to an angular speed of 240.0 rpm in 12.0 s. What is the moment of inertia of the flywheel?

User JSTL
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1 Answer

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Final answer:

To find the moment of inertia of the flywheel, use the equation T = Iα, where T is the torque, I is the moment of inertia, and α is the angular acceleration. Substitute the given values into the equations and solve for I.

Step-by-step explanation:

To find the moment of inertia of the flywheel, we can use the equation:

T = Iα

where T is the torque, I is the moment of inertia, and α is the angular acceleration.

In this case, we are given the torque and the time it takes to reach a certain angular speed, so we can calculate α using the equation:

α = ωf - ωi / t

where ωf is the final angular speed, ωi is the initial angular speed (which is 0 for a flywheel at rest), and t is the time.

Once we have α, we can substitute it into the first equation to solve for I.

Using the given values:

T = 32.0 Nm, ωf = 240.0 rpm = 240.0 * (2π rad/ min) / 60, ωi = 0, t = 12.0 s

we can calculate α and then substitute it into the equation:

I = T / α.

Your answer will be the moment of inertia of the flywheel.

User Adentum
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