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What is the perpendicular distance of the point (4,-3) from the line 3x-4y-1=0?

User Rayworks
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1 Answer

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Final answer:

The perpendicular distance of the point (4, -3) from the line 3x - 4y - 1 = 0 is calculated using the distance formula and is found to be 4.6 units.

Step-by-step explanation:

To calculate the perpendicular distance of a point from a line, we use the formula derived from the equation of the line:

d = |Ax1 + By1 + C| / √(A² + B²),

where d is the perpendicular distance, (x1, y1) is the point, and Ax + By + C = 0 is the equation of the line. For the point (4, -3) and the line equation 3x - 4y - 1 = 0, the formula becomes:

d = |(3)(4) + (-4)(-3) - 1| / √(3² + (-4)²),

which simplifies to:

d = |12 + 12 - 1| / √(9 + 16),

d = 23 / √25,

d = 23 / 5,

d = 4.6.

Therefore, the perpendicular distance of the point (4, -3) from the line 3x - 4y - 1 = 0 is 4.6 units.

User Giannis
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