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Given below are the number of successes and sample size for a simple random sample from a population. x=8,n=50,99% level a. Determine the sample proportion. b. Decide whether using the one-proportion z-interval procedure is appropriate. c. If appropriate, use the one-proportion z-interval procedure to find the confidence interval at the specified confidence level. d. If appropriate, find the margin of error for the estimate of p and express the confidence interval in terms of the sample proportion and the margin of error.

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Final answer:

a. The sample proportion is 0.16. b. The one-proportion z-interval procedure is appropriate. c. The 99% confidence interval is (0.054, 0.266). d. The margin of error is 0.106.

Step-by-step explanation:

a. Determine the sample proportion:

The sample proportion (p) can be calculated using the formula p = x/n, where x is the number of successes (8 in this case) and n is the sample size (50 in this case).

p = 8/50 = 0.16

b. Decide whether using the one-proportion z-interval procedure is appropriate:

In order to use the one-proportion z-interval procedure, the conditions np > 5 and n(1-p) > 5 must be satisfied, where p is the sample proportion.

Since np = 50 * 0.16 = 8 and n(1-p) = 50 * 0.84 = 42, both conditions are satisfied.

c. Use the one-proportion z-interval procedure to find the confidence interval:

A 99% confidence interval can be calculated using the formula p ± z * sqrt((p * (1-p)) / n), where z is the z-score corresponding to the desired confidence level (2.58 for 99% confidence).

p ± z * sqrt((p * (1-p)) / n)

0.16 ± 2.58 * sqrt((0.16 * 0.84) / 50)

0.16 ± 0.106

Confidence interval: (0.054, 0.266)

d. Find the margin of error and express the confidence interval:

The margin of error can be calculated by subtracting the lower limit of the confidence interval from the sample proportion.

Margin of error = 0.16 - 0.054 = 0.106

The confidence interval can be expressed as p ± margin of error.

Confidence interval: (0.054, 0.266)

User Jan Bluemink
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