Question

Suppose that we are conducting a two-tailed, single-sample, mean-average significance test with alpha =0.05 and with a sample of size n=21. What would be the value for t (critical)?

Determine E(eZ+99), where Z is a standard normal random variable.

Answer 1

The critical value for a two-tailed, single-sample, mean-average significance test with alpha = 0.05 and sample size n = 21 is -2.08. E(eZ+99) = 100.

Step-by-step explanation:

The critical value for a two-tailed, single-sample, mean-average significance test with alpha = 0.05 and a sample size of n = 21 would be -2.08.

To determine E(eZ+99), we need to find the expected value of 99 plus a standard normal random variable Z.

Since Z is a standard normal random variable, its mean is 0 and its standard deviation is 1.

Therefore, E(eZ+99) = E(e(0+1*Z)+99) = E(eZ) + 99.

The expected value of a standard normal random variable Z is 0 (E(Z) = 0), so E(eZ) =
`e^0` = 1.

Therefore, E(eZ+99) = 1 + 99 = 100.